问题描述:
cos(x-6分之π)=-3分之根3,则cosx+cos(x-3分之π)=

cosθ+cosφ = 2 cos[(θ+φ)/2] cos[(θ-φ)/2]
cosx+cos(x-π/3)
=2 cos[(x+x-π/3)/2] cos[(x-x+π/3)/2]
=2 cos(x-π/6) cosπ/6
=2(-3分之根3)(2分之根3)
=-1
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问题描述:
cos(x-6分之π)=-3分之根3,则cosx+cos(x-3分之π)=
cosθ+cosφ = 2 cos[(θ+φ)/2] cos[(θ-φ)/2]
cosx+cos(x-π/3)
=2 cos[(x+x-π/3)/2] cos[(x-x+π/3)/2]
=2 cos(x-π/6) cosπ/6
=2(-3分之根3)(2分之根3)
=-1
声明:有的资源均来自网络转载,版权归原作者所有,如有侵犯到您的权益
请联系本站我们将配合处理!